Solve the following system of equations by linear combination:
3x + 2y = 7
y = x – 4
(3, –1)
(2, 6)
(–1, 3)
(6, 2)
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OpenStudy (nikato):
Use substitution
OpenStudy (anonymous):
Substitution?
OpenStudy (nikato):
Yes, like what u did with the x in the last question
OpenStudy (anonymous):
This one isn't hard since they have already solved for y. Now plug in x-4 for y in the first equation. You get ... 3x + 2(x-4)=7. Now expand the paranthesis by distributing the 2 and we get 3x + 2x-8=7. Add like terms to get 5x-8=7 we're solving for x so move 8 to the other side and it becomes 5x=7+8 and that becomes 5x=15. divide both sides by 5 and get x = ?. Plug x into the second equation to get y...so y= ? - 4
OpenStudy (anonymous):
what do i substitute?
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OpenStudy (nikato):
The value of y into the first equation
OpenStudy (anonymous):
is it A?
OpenStudy (anonymous):
substitute x -4 for y in the first equation
OpenStudy (anonymous):
3x + 2-4=7? @Tay003
OpenStudy (anonymous):
3x + 2(x-4) =7
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OpenStudy (anonymous):
so whats the answer 0-0?
OpenStudy (anonymous):
im confused, are there more steps? @Tay003
OpenStudy (anonymous):
if you distribute you get 3x +2x -8=7 Always combine like terms so it 5x = 15 divide by 5 and you get the x value
OpenStudy (anonymous):
so 15/5?
OpenStudy (anonymous):
thats three so the first choice?
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