the frequency of oscillation of a mass m suspended bu a spring is v1. if the lenght of spring is cut to one third then the same mass oscillates with frequency v2 then relation between v1 and v2is?

Question

cybershadow · Answer

see frequency of string is f = n(v/2l)

cybershadow · Answer

now u can take l1 as = l and l2 = l/2

cybershadow · Answer

therefore v1 = n (v/2l) and v2 = n(v/2(l/2))

cybershadow · Answer

so v1/v2 = l/2l = 1/2

cybershadow · Answer

and v1 = 2v2 , Hope its clear :)

vincent-lyon.fr · Answer

@CyberShadow 
I think this question is not about compression or transverse waves travelling on a massive spring.
It is just a massless spring with a mass attached to it.
When you cut the length of spring, you change the overall spring constant.
This is why the mass-spring system will oscillate at a different frequency.

cybershadow · Answer

ah Yes! Nevermind

cybershadow · Answer

@Vincent-Lyon.Fr

cybershadow · Answer

i missread Spring as STRING

vincent-lyon.fr · Answer

lol! It sometimes happens to me too!

anonymous · Answer

If spring force constant remains the same, F = - k x and if we are ignoring
the mass of the spring, as usual, then the velocity will be unchanged.