Question

What is the solution to the integral below:

Answer 1

where is it?

Answer 2

\[\int\limits_{1}^{x} (2/x^2)\]

Answer 3

see it wud be 2(x^-2) inside the integral

Answer 4

as 2 is the constant we can take it out and therefore it is (x^-2) inside the integral

Answer 5

that will make it 2 * ( x^(-2+1)/-2+1)

Answer 6

put in the limits and solve it :)

Answer 7

Sorry I was gone for a second

Answer 8

Oh I see. We'll get 2x^-1/-1 = -2x^-1

Answer 9

+2

Answer 10

u forgot to insert the upper limit

Answer 11

it wud be 2(x^-1 -1)

Answer 12

Oh okay.

Answer 13

yes and to write it more simpler ,u can write it as 2(1/x-1)
= 2(1-x/x)