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Lim ( x^3 + 5x^2 – 7x – 35) / (x+5) x→-5
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did you check what happens if you plugin \(x=-5\) ?
thats what im learning now and i think you just do what spacelimbus said just plug it in
also note that you can write the nominator differently so it will cancel out with the denominator
btw its numerator
sorry, I still don't get it. I know the answer is 18 , but how???
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\[x^3 + 5x^2 – 7x – 35=(x+5)(x^2-7) \]
so you see that the \((x+5)\) from the denominator cancels out, you remain left with \(x^2-7\) now plugin \(x=-5\) will give you \((-5)^2-7=25-7=18\)
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