Question

Will someone help me with circles. I'm just not catching on with it and I have 2 assignments to do with them..

Answer 1

what is the question?

Answer 2

number 1 right now but I need help with it all I just don't understand, im sure if you help me with 1 ill get a few others

Answer 3

ignore the answer to #1 im just trying to try stuff to help but its not helping that I don't have multiple choice

Answer 4

I think they want you to know (remember) that the measure of an arc is equal to the measure of the central angle. (the central angle is the same as the measure of the arc and vice versa)

Answer 5

so that angle will alao be 102 degrees?

Answer 6

yes

Answer 7

also*

Answer 8

thank you

Answer 9

for Q2, they want the smaller central angle, but give you the "bigger angle"
remember all the way around is 360º

Answer 10

okay, so I would take 360-302=58. and then 58 degrees is what that angle would be?

Answer 11

yes

Answer 12

For Q3, you should know (memorize) an inscribed angle is ½ of the central angle (or, the same thing, ½ of its arc)

Answer 13

im working that one out and ill tell you what I got and see if im doing it right

Answer 14

okay, I did 360-(x+45) then got it down to 315-x then I set the angle to it
x=315-x and got 157.5 and then took half of that and got 78.75

Answer 15

pretty close.
arc AB= 315 - x

the inscribed angle ACB is ½ of arc AB
in other words
<ACB = ½ (315-x)
we know <ACB is x, so this is the same as
x = ½ (315-x)

notice we have to use the ½ idea first (not at the end)

Answer 16

ohh. im still stuck. Would I still get 78.75 putting 1/2 first

Answer 17

did you start with
\[ x = \frac{1}{2}(315-x) \]?

Answer 18

the first step could be, multiply both sides by 2
what do you get ?

Answer 19

2x=630-2x???

Answer 20

like this
\[ 2 \cdot x =2 \cdot \frac{1}{2}(315-x)\]
the 2 * ½ is 1 so this becomes
\[ 2x = 315 -x \]
now add +x to both sides.

Answer 21

3x=315
105

Answer 22

yes. See if you can make sense of what we did to solve this one (which was a bit tricky)

Answer 23

I understand but then I don't. But I had an example in the lesson and wrote down step by step but that last part got me

Answer 24

The first trick part is finding arc AB is 315-x
you did that.

then you need to know that angle ACB is ½ of arc AB
angle ACB = ½ (315 -x)

they tell you angle ACB is equal to x, so you get the equation
\[ x = \frac{1}{2} (315-x) \]
to solve you need to know algebra.

Answer 25

okay thanks I understand that a lot better. The only question I have about the next one is how would I solve it without the major arc. I thought I had to take the major arc minus 360 then divide that by 2 and set that answer equal to each equation

Answer 26

for Q4, angle x is how much of arc WZ ?

Answer 27

half?

Answer 28

yes. now what about angle y? what arc is it ½ of ?

Answer 29

WZ

Answer 30

in other words angle x = WZ/2 and angle y = WZ/2
that means angle x equals angle y

Answer 31

so x+2=3x-40

Answer 32

yes. now it's algebra ....

Answer 33

thank you im going to work it out

Answer 34

I got 42?

Answer 35

you need to practice your algebra.

x+2=3x-40
add -x to both sides:
-x+x+2 = 3x - x - 40
simplify:
2 = 2x -40

can you finish?

Answer 36

yes, equations are usually my easiest thing. I think I just need to focus more. I think i got the rest of the assignment. If I have any more questions i'll come to you. Thank you! you helped a lot:)

Answer 37

@phi I ended up getting a 100 on this assignment, thank you