Question

This is a trigonometric function question.

Answer 1

Find the value of Tan(a-b) if a=3/5 and b=5/13

\[Tan(\frac{3 }{5}-\frac{5 }{13} )\]
I did, using the Cos(a-b) and Sin(a-b) identities so far.
\[Tan(\frac{3 }{5}-\frac{5 }{13} )= \frac{Sin(\frac{3 }{5}-\frac{5 }{13} ) }{Cos(\frac{3 }{5}-\frac{5 }{13} )} \]I'll post this now becuase I might disconnect, but i know how to go a little farther and then I am stock, pliz wait....

Answer 2

...

Answer 3

Are those inverse functions?

Answer 4

\[\huge\color{blue}{ \frac{ Sin\frac{3 }{5} Cos\frac{5 }{13} -Cos\frac{3 }{5}Sin\frac{5 }{13} }{ Cos\frac{3 }{5}Cos\frac{5 }{13}+Sin \frac{3 }{5}Sin \frac{5 }{13} } } \]

No, not inverse functions, just solving.

Answer 5

I doubt if they are not inverse functions. The numbers 3, 5, 13 only pop up in the case of sides, not angles. Well anyway, interesting question (?).

Answer 6

\[3^2+\color{blue} { 4^2 } =5^2~~~~and~~~~~~~5^2+\color{blue} { 12^2 } =13^2 \]

they are AGAIN, TRIGonometric, not inverse functions.

Answer 7

@ParthKohli
\[Tan = \frac{ o }{ a }\]
\[\sin = \frac{ o }{ h }\]
\[\cos = \frac{ a }{ h }\]

\[\frac{ \sin}{ \cos } = \frac{ o/h}{ a/h }\]
\[= \frac{ o }{ a } = \tan\]
thus,
\[\tan(a) = \frac{ \sin(a) }{ \cos(a) }\]

Answer 8

Yeah, I'm fine with that.

Answer 9

I know those, SOHCAHTOA, but not sure how to apply.

Answer 10

Trigonometric functions are of angles.

Answer 11

And this is?

Answer 12

@StudyGurl14 yeah, thanks.

Answer 13

@SolomonZelman , I was just showing @ParthKohli them because she thinks they are inverse functions

Answer 14

see my last huge-blue fraction? that's where I got up to.

Answer 15

We do not take the sin, cos or tan of sides, but angles.

Answer 16

Well, anyway, good luck.

Answer 17

What are youtrying to say? there is a mistake in what I did so far? please point it out then. If not then idk what is your point.

Answer 18

true, @ParthKohli , you take the inverse of sin, cos, tan, of sides to find the angles. I see what you're saying

Answer 19

I need help continuing, not arguing about the definition of trigonometric functions.

Answer 20

lol @SolomonZelman

Answer 21

There is no way to continue manually.

Answer 22

areyou making me repost the question saying I won't help you for whatever reason, or what the hack is going on (osrry) I just need help if that's not hard. This shouldn't be hard for OS, common guys. Also I am not deadly stupid and workable.

Answer 23

I'm sorry to interrupt you.

Answer 24

WHAT?!

Answer 25

I'm trying to remember other trig ratios (like the tan = sin/cos)...
Also, @ParthKohli , there could be such thing of 3/5 of a degree....

Answer 26

I know I think!

Answer 27

You are correct, but whoever assigned this problem should know that there isn't a workable solution to this problem.

Answer 28

http://en.wikipedia.org/wiki/Trigonometry#Standard_identities

Answer 29

I don't have a calculator for trigonometric functions can someone tell me what \[Sin^{-1}~3/5,~~Cos^{-1}~3/5,~~Sin^{-1}~5/13,~~Cos^{-1}~5/13\]are ?

Answer 30

I THINK YOU MEAN
TAN A=3/5
TAN B=5/13

Answer 31

YEs!

Answer 32

sin-1 (3/5) = apprx. 36.8699

Answer 33

DUDE, THOSE ARE INVERSE FUNCTIONS

Answer 34

the ones I ported just now, yes

Answer 35

cos^-1 (3/5) = apprx. 53.1301

Answer 36

I am redoing this.

3/5-5/13+ I'll solve

Answer 37

Well, take it as 37 and 53.

Answer 38

sin^-1 = 5/13 = apprx. 22.6199