Question

I'm gonna post some screen shots of 5 of my problems. Can someone check them for me and make sure that I have all of the correct answers?

Answer 1

1 & 2 are right

Answer 2

Okay, thank you. Do you know how the other 3 are? :)

Answer 3

3 is right

Answer 4

5 is correct

Answer 5

I meant 5...

Answer 6

Are 3 & 4 incorrect?

Answer 7

3 is correct. 4 is incorrect.

Answer 8

#4 is incorrect. You answered with 4 as the value of x to solve

\[3x+y=6\]\[6x+2y=8\]
Let's see what \(y\) would be in the first equation, if \(x = 4\)
\[3(4)+y=6\]\[12+y=6\]\[y=-6\]
But those same values of \(x,y\) must work in the second equation. Do they?
\[6(4)+2(-6)=8\]\[24-12=8\]Oops!

Answer 9

4 is wrong...those are parallel lines. They share nothing in common

Answer 10

3 is right

Answer 11

If you double the first equation, you do not get the second equation, although doubling the left side of the first equation gives you the left side of the second equation. That means they are parallel.

Answer 12

Would There is no x value as there is no solution to the system. be the correct answer for 4?

Answer 13

In general, if you solve the system of equations and get a true statement such as \(0=0\) that means there are infinitely many solutions (the lines are identical). If you get a false statement such as \(0=2\) that means the lines are parallel, and there are no solutions (they never cross, clearly).

\[3x+y=6\]\[6x+2y=8\]Multiply first equation by -2 and add them together:
\[-6x-2y=-12\]\[6x+2y=8\]-------------\[0x+0y=-4\]\[0=-4\]No solutions

Answer 14

Okay, thank you all for your help! It has helped me out a ton!!! =D