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Will medal and fan first to answer! Write the equation direct variation that includes the point (-6,2).
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Direct variation is \[\LARGE y=kx\] You are given \[\LARGE (-6,2)=(x, y)\] So plug them in: \[\LARGE 2=-6k\]
The general formula for "direct variation" is y=kx, where k is a constant of proportionality. Simply substitute x--6 and y=2 into that equation.
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Find k.
Right^ That was just the first part.
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Once you solve for k, plug that back into \[\LARGE y=kx\]
Thank you all your practically life savers!
Thank you, Luigi. You were right on target and I'm sorry I didn't acknowledge that sooner.
You're welcome, and no worries~
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