Question

PLEASE HELP ME !! What is the equation in standard form of the line which passes through (4, −2) and has a slope of −3?

Answer 1

@phi

Answer 2

@Callisto

Answer 3

@jdoe0001

Answer 4

Notice they give you a point and a slope. Do you know the point-slope formula for a line?

Answer 5

x2-x1
y2-y1 ?

Answer 6

that looks like how to find the slope (but it's upside down)
see http://www.freemathhelp.com/point-slope.html

Answer 7

once you can write down the equation in point slope form, you then change it into standard form

the standard form of a line is in the form Ax + By = C where A is a positive integer, and B, and C are integers.

Answer 8

how do you put it in point slope form?

Answer 9

did you look at the site posted up above?

Answer 10

i can't open it

Answer 11

\[ y - y_1 = m(x-x_1) \]

Answer 12

-2 -2 = -3(4-4) ?

Answer 13

the plain x and y are left as letters.
the \( (x_1,y_1) \) stand for the x and y *numbers* that they give you

Answer 14

y - (-2) = -3(x - 4)

Answer 15

yes. The next step is change it into
Ax + By = C where A is a positive integer, and B, and C are integers.

the first step is distribute the -3 (multiply all the terms inside the parens by -3)
also change y - -2 into y+2

Answer 16

y + 2 = -3x +12

Answer 17

now add +3x to both sides. (put the x term in front of the y term because we want the answer to match with Ax + By = C )

Answer 18

then add -2 to both sides.

Answer 19

3x + y = 10

Answer 20

thats correct?

Answer 21

yes

Answer 22

thank you so much

Answer 23

yw