Help me please solve this rational expression? (1/3+x) + (1/x) = (1/2)
Here is the original word problem:
i posted the same thing about 25 minutes ago and for some reason no one could solve.. so.. o.o
\[\frac{ 1 }{ t+3 }+\frac{ 1 }{t }=\frac{ 1 }{2 }\] \[\frac{ t+t+3 }{t \left( 1+t \right) }=\frac{ 1 }{ 2 }\] \[2\left( 2t+3 \right)=t ^{2}+t,t ^{2}+t-4t-6=0,~t ^{2}-3t-6=0\] solve it.
Woah. o.o What's that bottom part. o.e
correction ,write 3+t in place of 1+t
I'm confused. I'm not supposed to simplify here. I'm finding an actual numerical value.
WHO CAME UP WITH THE EXPRESSION?
I HAVE NO IDEA. stupid common core.. @nincompoop
OKAY
I've seen it solved before. Somehow, the x needs to get isolated but I don't know how to do that with rational expressions.
\[4t+6=3t+t ^{2},t ^{2}-t-6=0\]
\[t ^{2}-3t+2t-6=0,t \left( t-3 \right)+2\left( t-3 \right)=0\] \[\left( t-3 \right)\left( t+2 \right)=0,t=3,t=-2\] rejecting t=-2 t=3
OH, thank you!
So if I plugged 3 into the original equation, it should satisfy?
you are correct.
thank you!
\[\frac{ 1 }{6 }+\frac{ 1 }{3 }=\frac{ 1+2 }{ 6 }=\frac{ 3 }{6 }=\frac{ 1 }{ 2 }\]
np
So the expression above, it simplifies to 2(2t+3)? this one: x+x+3/x(3+t)
i mean 2x. My teacher doens't like it when I use anything other than x, y or z lol
I have used t only because it is time.Otherwise you can use any variable x,y,z,a,b,...etc.
But that's what it simplifies to?
Nvm, got it! Thanks!
Join our real-time social learning platform and learn together with your friends!