Question

So can someone help me solve this equation?? s = (-1/2*R*C) +/- ((1/2*R*C)^2 - (1/L*s))^1/2 . I am given values for R, C, and L. The problem being the s inside the parenthesis.

Answer 1

@ybarrap , a stood for plus and minus in matlab.

Answer 2

well it stood for [-1, 1] which performed the same task.

Answer 3

Sorry but Im still so lost how -1/2rc becomes -RC/2

Answer 4

$$
s = \cfrac{-R C}{2} \pm \sqrt {\left (\cfrac{R C}{2}\right )^2 - \cfrac{s}{L}}\\
\implies\\
\cfrac{-R C}{2} + \sqrt {\left (\cfrac{R C}{2}\right )^2 - \cfrac{s}{L}}=\cfrac{-R C}{2} - \sqrt {\left (\cfrac{R C}{2}\right )^2 - \cfrac{s}{L}}\\
-\cfrac{R C}{2} + \sqrt {\left (\cfrac{R C}{2}\right )^2 - \cfrac{s}{L}}+
\cfrac{R C}{2} + \sqrt {\left (\cfrac{R C}{2}\right )^2 - \cfrac{s}{L}}=0\\
2\sqrt {\left (\cfrac{R C}{2}\right )^2 - \cfrac{s}{L}}=0\\
\left (\cfrac{R C}{2}\right )^2 - \cfrac{s}{L}=0\\
\cfrac{s}{L}=\left (\cfrac{R C}{2}\right )^2\\
s=L\left (\cfrac{R C}{2}\right )^2\\
$$

Answer 5

Since you have that s= some number \(\pm\) something, we then know that some number \(+\) something=some number \(-\) something and so 2\(\times\)something=0.