What was the hiker's average velocity during part A of the hike?
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@whpalmer4 I think its 5.0km/h/ north
what are the units for the time? minutes:seconds, or hours:minutes?
hours
Okay, so if the start time is 1:00 and the end time is 1:30, how much time passes between them?
30 minutes?
That's what I think, too :-) So if you walk 5 km in 30 minutes, what is your average speed?
\[d = r * t\]\[r = \frac{d}{t}\]where \(d\) is distance, \(r\) is rate or speed, \(t\) is time
so 5km=r*30?
well, yes, but it's possible we want to talk in terms of km/hr rather than km/min when talking hiking speeds
so r=5km/30
well, we need a unit on that 30, for starters. and if we are talking about hours, it isn't 30 hours, it's 0.5 hours because there are 60 minutes in an hour
oh duh so r=5/0.5?
yes, but it is important to keep those units! \[r = \frac{5 \text{ km}}{0.5 \text{ hour}}=\]
what do you get for the numeric part of that?
I got 10
Right. so the speed of the hiker is \(10 \text{ km/hr}\). To make that a velocity, we need to add a direction, which I think you've already suggested is N.
so 10km/0.5hrs.
No! 5 km/0.5 hrs = 10 km/1 hr or 10 km/hr. he went 5 km in 0.5 hrs, so the rate is 5 km/ 0.5 hr = 10 km/hr. Do you see how I went from one to the other?
oh yeah I do.
It's like saying if you do 3 problems in 30 minutes, how many problems do you do in an hour? how many problems per hour can you do?
so are we agreed that 10 km/hr is the speed of the hiker? (realistically, I'm not — he'd have to be jogging to do that! :-)
I got 0.16666
where did you get that? and what is the unit?
well 10km/1hr.
Yes, 10 km/hr is the rate. But how do you get 0.16666? Oh, you're dividing 10 km by 60 minutes, right?
yes
Yeah, there's no reason to do that, unless you are looking to express the speed in km/minute.
oh ok thanks! :)
So 10 km/hr N would be the velocity
barring some hidden instruction to use a different set of units
So to find the rate, you just divide the number done by the time it took. Drive 300 miles in 6 hours, rate is 300 miles / 6 hours = 50 miles/hour. Dig 27 holes in your back yard in 9 hours, rate is 27 holes /9 hours = 3 holes/hour.
Lots of story problems can be solved most conveniently by finding the rates involved. For example: you've got a swimming pool you're trying to fill up. With your garden hose running into the pool, it will take 4 hours. With your neighbor's super-thick garden hose running into the pool instead, it would take 2 hours. How long does it take to fill up if you use both hoses at the same time? Filling with your hose, the rate is 1/4 of a pool per hour. Filling with the neighbor's hose, the rate is 1/2 of a pool per hour. Together, they fill 1/4 + 1/2 = 3/4 of a pool per hour, so to fill the entire pool takes 1 pool / (3/4 pool/hour) = 4/3 of an hour or 1 hour 20 minutes.
ok thanks!
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