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OpenStudy (anonymous):

What was the hiker's average velocity during part A of the hike?

OpenStudy (anonymous):

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OpenStudy (anonymous):

@whpalmer4 I think its 5.0km/h/ north

OpenStudy (whpalmer4):

what are the units for the time? minutes:seconds, or hours:minutes?

OpenStudy (anonymous):

hours

OpenStudy (whpalmer4):

Okay, so if the start time is 1:00 and the end time is 1:30, how much time passes between them?

OpenStudy (anonymous):

30 minutes?

OpenStudy (whpalmer4):

That's what I think, too :-) So if you walk 5 km in 30 minutes, what is your average speed?

OpenStudy (whpalmer4):

\[d = r * t\]\[r = \frac{d}{t}\]where \(d\) is distance, \(r\) is rate or speed, \(t\) is time

OpenStudy (anonymous):

so 5km=r*30?

OpenStudy (whpalmer4):

well, yes, but it's possible we want to talk in terms of km/hr rather than km/min when talking hiking speeds

OpenStudy (anonymous):

so r=5km/30

OpenStudy (whpalmer4):

well, we need a unit on that 30, for starters. and if we are talking about hours, it isn't 30 hours, it's 0.5 hours because there are 60 minutes in an hour

OpenStudy (anonymous):

oh duh so r=5/0.5?

OpenStudy (whpalmer4):

yes, but it is important to keep those units! \[r = \frac{5 \text{ km}}{0.5 \text{ hour}}=\]

OpenStudy (whpalmer4):

what do you get for the numeric part of that?

OpenStudy (anonymous):

I got 10

OpenStudy (whpalmer4):

Right. so the speed of the hiker is \(10 \text{ km/hr}\). To make that a velocity, we need to add a direction, which I think you've already suggested is N.

OpenStudy (anonymous):

so 10km/0.5hrs.

OpenStudy (whpalmer4):

No! 5 km/0.5 hrs = 10 km/1 hr or 10 km/hr. he went 5 km in 0.5 hrs, so the rate is 5 km/ 0.5 hr = 10 km/hr. Do you see how I went from one to the other?

OpenStudy (anonymous):

oh yeah I do.

OpenStudy (whpalmer4):

It's like saying if you do 3 problems in 30 minutes, how many problems do you do in an hour? how many problems per hour can you do?

OpenStudy (whpalmer4):

so are we agreed that 10 km/hr is the speed of the hiker? (realistically, I'm not — he'd have to be jogging to do that! :-)

OpenStudy (anonymous):

I got 0.16666

OpenStudy (whpalmer4):

where did you get that? and what is the unit?

OpenStudy (anonymous):

well 10km/1hr.

OpenStudy (whpalmer4):

Yes, 10 km/hr is the rate. But how do you get 0.16666? Oh, you're dividing 10 km by 60 minutes, right?

OpenStudy (anonymous):

yes

OpenStudy (whpalmer4):

Yeah, there's no reason to do that, unless you are looking to express the speed in km/minute.

OpenStudy (anonymous):

oh ok thanks! :)

OpenStudy (whpalmer4):

So 10 km/hr N would be the velocity

OpenStudy (whpalmer4):

barring some hidden instruction to use a different set of units

OpenStudy (whpalmer4):

So to find the rate, you just divide the number done by the time it took. Drive 300 miles in 6 hours, rate is 300 miles / 6 hours = 50 miles/hour. Dig 27 holes in your back yard in 9 hours, rate is 27 holes /9 hours = 3 holes/hour.

OpenStudy (whpalmer4):

Lots of story problems can be solved most conveniently by finding the rates involved. For example: you've got a swimming pool you're trying to fill up. With your garden hose running into the pool, it will take 4 hours. With your neighbor's super-thick garden hose running into the pool instead, it would take 2 hours. How long does it take to fill up if you use both hoses at the same time? Filling with your hose, the rate is 1/4 of a pool per hour. Filling with the neighbor's hose, the rate is 1/2 of a pool per hour. Together, they fill 1/4 + 1/2 = 3/4 of a pool per hour, so to fill the entire pool takes 1 pool / (3/4 pool/hour) = 4/3 of an hour or 1 hour 20 minutes.

OpenStudy (anonymous):

ok thanks!

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