How can (1/4)x-3=(1/2)x+8 be set up as a system of equations? I got this wrong on the test with an answer of 4y-4x=-12 and 2y-2x=16. I'd like to know what I did wrong and of course, they don't tell you.
\[\frac{ 1 }{ 4 }x-3=\frac{ 1 }{ 2 }x+8\]
@satellite73 ... if you get a chance, can you explain this to me?
i guess you could write \[\frac{ 1 }{ 4 }x-3=y\\ \frac{ 1 }{ 2 }x+8=y\] but that seem silly
It does seem silly, but you are probably correct!
or you could write \[x-4y=12\\ x-2y=-16\] both are equally ridiculous because you have it right in the form to solve
The available answers other than the one I chose were:
4y + 4x = −12 2y + 2x = 16
i see the problem you multiplied the first one by 4, but \(4\times \frac{1}{4}=x\) not \(4x\)
4y − x = −12 2y − x = 16
4y + x = −12 2y + x = 16
Ok, I see where I got the x part wrong
\[x-4y=12\\ x-2y=-16\] is what i got multiply both sides by \(-1\) and get \[4y-x=-12\\ 2y-x=16\]
what a weird arbitrary question
Any idea of why they would do that instead of leaving it as the x-4y and x-2y?
I've never seen any problem like this. O.e :S
lol @tHe_FiZiCx99
@satellite73 ... I was going to send you a message, but it says you only accept messages from someone you've fanned
C. 4y + x = −12 2y + x = 16 And D. 4y − 4x = −12 2y − 2x = 16 Are wrong , just took the test
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