Question

the sum of the digits in a two digit number is 12, if the digits are reversed, the new number is 18 more than the original, find the original number

Answer 1

Let

t = tens digit
u = units digit

we are told that "the sum of the digits in a two digit number is 12" so this means

t + u = 12

Answer 2

Solve for t to get

t + u = 12

t = 12 - u

Answer 3

Then we're told that "if the digits are reversed, the new number is 18 more than the original" which translates to this equation

10u+t = 10t+u + 18

Now plug in t = 12 - u to get

10u+12-u = 10(12-u)+u + 18

From here, you solve for u. Tell me what you get.

Answer 4

im stupid so I cant solve that

Answer 5

I'll get you started

10u+12-u = 10(12-u)+u + 18

10u+12-u = 120-10u+u + 18

9u + 12 = -9u + 138

u = ???

Answer 6

is the original number 75?

Answer 7

close, it's actually 57

Answer 8

thank you

Answer 9

you're welcome