Question

i need help with algebra 2 please? ill medal:)

Answer 1

@UsukiDoll

Answer 2

\[\sqrt[4]{1296x^{16}y^{12}}\]

Answer 3

@StudyGurl14 do you know what it would be simplified?

Answer 4

\[\sqrt[4]{(81 * 16)(x^{4}x^{4}x^{4}x^{4})(y^{4}y^{4}y^{4})}\]

Answer 5

thats not an option..?

Answer 6

I'm not done

Answer 7

ooh..lol ok:)

Answer 8

@StudyGurl14 could you possibly hurry? i have to leave soon..:/

Answer 9

\[(4)(\left| x \right| \left| x \right| \left| x \right| \ \left| x \right|)(\left| y \right|\left| y \right|\left| y \right|)\sqrt[4]{81}\]

\[4\left| x^{4} \right|\left| y^{3} \right|\sqrt[4]{9 * 9}\]

Answer 10

If you're in a hurry, it is A. btw

Answer 11

oh, ok thank you very much:)

Answer 12

mmm im not sure about that...

Answer 13

hold on! @Hailey553 I made a mistake. It isn't A!

Answer 14

what is 6^4 and 36^4?

Answer 15

haha! ok:)

Answer 16

\[\sqrt[4]{3^{4}} = 3\]
so 3 *4 = 12
hm...I made amistake cause that's not an option

Answer 17

try taking it backwards...

instead of thinking of 4th root. Take everything to the 4th power.

Answer 18

so, which one would it be?

Answer 19

Oh it is B or C. something with the 6

Answer 20

its B if you have to leave right now

Answer 21

but stay for explaination

Answer 22

I made mistake up there with the 16

Answer 23

\[\sqrt[4]{1296x ^{16}y ^{12}}=\left( 6^{4}\left( x ^{4} \right)^{4} \left( y ^{3} \right)^{4}\right)^{\frac{ 1 }{ 4 }}\]
\[=\left\{ \left( 6x ^{4}y ^{3} \right)^{4} \right\}^{\frac{ 1 }{4 }}=6x ^{4}y ^{3}\]

Answer 24

nice job @surjithayer

Answer 25

don't forget the absolute value signs though.

Answer 26

thank you guys so much!

Answer 27

@surjithayer did it a much better way than I did @Hailey553. You should fan + medal him/her