Rite my concept of Induced Emf is not that clear and i m stuck with these question , any help mite be very useful :) A long this solenoid has 900 turns/m and radius 2.5 cm.The current in the solenoid is increasing at a uniform rate of 60A/s.What is the magnitude of induced electric field at a point at a distance -.5 cm from axis of solenoid I know that El = s dB/dt but i m not sure wheather i shud take l as =-0.5 or 2pi(-0.5) ?WOOP WOOP SOLVED! ,
@ganeshie8 Mind helping? 0:)
I need some help ! urgently
I think you need to use that formula
but what is L?
\[muNi/2a\]
0.5 or 2 pi (0.5) ??
Why do you need to use L?
i need to find induced emf, which which cud be found using El = A dB/dt formula
do we have another formula for it as well? o.O
Yeah! just give me a moment
I'm not too sure... Are you sure it's the magnitude of the induced ELECTRIC field that you need to find?
yeah
L = \[\mu(n)^2V\]
thats the magnetic field, B
V=Sl is the volume of the solenoid
ohh i c
No... that's the formula for the inductance of a solenoid
S is the cross-sectional area of the solenoid
no actually l here is not the INDUCTANCE , its some length
And l is the length of the solenoid n=(N/l) is the number of turns per unit length
the concept of induced electric field is that, line integral of E = change in flux
l is the length, I just told you :)
N is the number of turns.
ah i got it
so it wud be El = sdB/dt
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so l is length of solenoid?
Yeah! l is the length of the solenoid
0.5?
The point they're considering is inside the solenoid.. because it's -0.5
yea
actually in the equation the things we know are S, N/l , di/dt
i m cofused of l , that is not the length of the solenoid i guess, its the distance from the axis of solenoid at the point where electric field is asked,
i m confused if it shud be 2pi(l) or just l
Probably 2pi l because they haven't mentioned the length right? Just the radius
they have asked us to find it at a distance of 0.5 , so it i shud put it as 0.5 or 2pi(0.5) ?
Try both and tell me what you come up with.. It's got to be one or the other..
aha dude , using 2pi(o.5) gave the right answer, to naive of me to not try and match values with answer , Thanx :)
No problem :) Best of luck! :)
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