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Physics 14 Online
OpenStudy (cybershadow):

Rite my concept of Induced Emf is not that clear and i m stuck with these question , any help mite be very useful :) A long this solenoid has 900 turns/m and radius 2.5 cm.The current in the solenoid is increasing at a uniform rate of 60A/s.What is the magnitude of induced electric field at a point at a distance -.5 cm from axis of solenoid I know that El = s dB/dt but i m not sure wheather i shud take l as =-0.5 or 2pi(-0.5) ?WOOP WOOP SOLVED! ,

OpenStudy (cybershadow):

@ganeshie8 Mind helping? 0:)

OpenStudy (cybershadow):

I need some help ! urgently

OpenStudy (potatoes.ramu):

I think you need to use that formula

OpenStudy (cybershadow):

but what is L?

OpenStudy (potatoes.ramu):

\[muNi/2a\]

OpenStudy (cybershadow):

0.5 or 2 pi (0.5) ??

OpenStudy (potatoes.ramu):

Why do you need to use L?

OpenStudy (cybershadow):

i need to find induced emf, which which cud be found using El = A dB/dt formula

OpenStudy (cybershadow):

do we have another formula for it as well? o.O

OpenStudy (potatoes.ramu):

Yeah! just give me a moment

OpenStudy (potatoes.ramu):

I'm not too sure... Are you sure it's the magnitude of the induced ELECTRIC field that you need to find?

OpenStudy (cybershadow):

yeah

OpenStudy (potatoes.ramu):

L = \[\mu(n)^2V\]

OpenStudy (cybershadow):

thats the magnetic field, B

OpenStudy (potatoes.ramu):

V=Sl is the volume of the solenoid

OpenStudy (cybershadow):

ohh i c

OpenStudy (potatoes.ramu):

No... that's the formula for the inductance of a solenoid

OpenStudy (potatoes.ramu):

S is the cross-sectional area of the solenoid

OpenStudy (cybershadow):

no actually l here is not the INDUCTANCE , its some length

OpenStudy (potatoes.ramu):

And l is the length of the solenoid n=(N/l) is the number of turns per unit length

OpenStudy (cybershadow):

the concept of induced electric field is that, line integral of E = change in flux

OpenStudy (potatoes.ramu):

l is the length, I just told you :)

OpenStudy (potatoes.ramu):

N is the number of turns.

OpenStudy (cybershadow):

ah i got it

OpenStudy (cybershadow):

so it wud be El = sdB/dt

OpenStudy (cybershadow):

|dw:1389438837226:dw|

OpenStudy (cybershadow):

so l is length of solenoid?

OpenStudy (potatoes.ramu):

Yeah! l is the length of the solenoid

OpenStudy (cybershadow):

0.5?

OpenStudy (potatoes.ramu):

The point they're considering is inside the solenoid.. because it's -0.5

OpenStudy (cybershadow):

yea

OpenStudy (cybershadow):

actually in the equation the things we know are S, N/l , di/dt

OpenStudy (cybershadow):

i m cofused of l , that is not the length of the solenoid i guess, its the distance from the axis of solenoid at the point where electric field is asked,

OpenStudy (cybershadow):

i m confused if it shud be 2pi(l) or just l

OpenStudy (potatoes.ramu):

Probably 2pi l because they haven't mentioned the length right? Just the radius

OpenStudy (cybershadow):

they have asked us to find it at a distance of 0.5 , so it i shud put it as 0.5 or 2pi(0.5) ?

OpenStudy (potatoes.ramu):

Try both and tell me what you come up with.. It's got to be one or the other..

OpenStudy (cybershadow):

aha dude , using 2pi(o.5) gave the right answer, to naive of me to not try and match values with answer , Thanx :)

OpenStudy (potatoes.ramu):

No problem :) Best of luck! :)

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