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\[\frac{ x^{5} }{x ^{3} } = \frac{ 16x^{3} }{ x^{3} }\]
\[x^{5} = 16x ^{3}\]
consider the both equation dividing both sies by x3 gives i.e and hence however, as well as these two solutions of x = 4 and x = -4 there is another value for x that satisfies the original equation. what is this 3rd solution tot he original equation?
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