Peter has 10 different books. 7 of them are novels and 3 are comics. In how many ways can Peter arrange 7 books on a shelf with 5 novels on the left and 2 comics on the right. my answer: 7C5 * 3C2 = 63 is it correct? @ganeshie8
yes right !!
As far as what I remember, yes....
oh, thanks! do you mind i post another question is this post?
was it for me ?
Another question: In a class, 6 students are divided into 3 groups of 2 students each. In how many ways can the 3 groups be formed? my answer: 6C2=15 i don't think it'll be a simple question.
@digitalmonk what?
first 2 students (for the 1st group) can be selected in 6C2 ways, when two students have been selected for next group 4C2, for next group 1 way total ways = (6C2x4C2x1)/ 3!
for your first question the order that you arrange the books and comics matter so you should be using permutation and not combinations.
but arranging books can be repeated...isn't it?
the books are said to be different so any permutation will give a unique arrangement. Therefore you need permutations and not combinations.
oh my god @@
so what's the correct working step?
just replace C with P (replace the combination with a permutation)
really ... ? ok...thanks..
15120?!
but the three groups formed are identical, the according to the problem "the order" inside each group in not of importance !!
@digitalmonk i think 63 is the answer lol. We are correct?
The first question is asking for the number of "arrangements". This is a permutation.
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