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Mathematics 22 Online
OpenStudy (anonymous):

Peter has 10 different books. 7 of them are novels and 3 are comics. In how many ways can Peter arrange 7 books on a shelf with 5 novels on the left and 2 comics on the right. my answer: 7C5 * 3C2 = 63 is it correct? @ganeshie8

OpenStudy (anonymous):

yes right !!

OpenStudy (anonymous):

As far as what I remember, yes....

OpenStudy (anonymous):

oh, thanks! do you mind i post another question is this post?

OpenStudy (anonymous):

was it for me ?

OpenStudy (anonymous):

Another question: In a class, 6 students are divided into 3 groups of 2 students each. In how many ways can the 3 groups be formed? my answer: 6C2=15 i don't think it'll be a simple question.

OpenStudy (anonymous):

@digitalmonk what?

OpenStudy (anonymous):

first 2 students (for the 1st group) can be selected in 6C2 ways, when two students have been selected for next group 4C2, for next group 1 way total ways = (6C2x4C2x1)/ 3!

OpenStudy (zarkon):

for your first question the order that you arrange the books and comics matter so you should be using permutation and not combinations.

OpenStudy (anonymous):

but arranging books can be repeated...isn't it?

OpenStudy (zarkon):

the books are said to be different so any permutation will give a unique arrangement. Therefore you need permutations and not combinations.

OpenStudy (anonymous):

oh my god @@

OpenStudy (anonymous):

so what's the correct working step?

OpenStudy (zarkon):

just replace C with P (replace the combination with a permutation)

OpenStudy (anonymous):

really ... ? ok...thanks..

OpenStudy (anonymous):

15120?!

OpenStudy (anonymous):

but the three groups formed are identical, the according to the problem "the order" inside each group in not of importance !!

OpenStudy (anonymous):

@digitalmonk i think 63 is the answer lol. We are correct?

OpenStudy (zarkon):

The first question is asking for the number of "arrangements". This is a permutation.

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