If f(x)=1/^3SQRTx Find F''(x)
Are you certain you've typed the problem in as presented to you? that 1/^3 makes me nervous! Could you possibly enter your problem statement using the equation editor, below?
\[\Large\bf\sf f(x)\quad=\quad \frac{1}{\sqrt[3]{x}}\]Is this the function? Cube root in the bottom?
Yup thats the one
HHH: Note that if zepdrix is correct, "SQRT" does not belong in the problem statement. Instead, type "CUBE ROOT OF X."
The equation editor uses sqrt for every root.. :) So maybe it was presented that way.
Mybest advice at this point is to rewrite zepdrix' correct expression as y=x^(-1/3). You familiar with that?
I don't know how to use this website much , anyways , anyone know how to find it?
So, in the Equation Editor, \[y=\frac{ 1 }{ 3^{(1/3)} }=y=3^{(-1/3)}\]
@mathmale I just need all the working out and steps at this point, cause fractions make me cry
Oh yeah i got it from there , thanks man
OK. This truly is the easiest way to solve this problem. AFter having re-written the original function, finding the 1st and 2nd derivatives should be a snap. You're welcome! :)
Actually, I've made a mistake. Should have given you:
\[y=x ^{-1/3}\]
Nobody's perfect, least of all I!
I really appreciate the time you're putting into my question.. True that, we all make mistakes, wish me luck man , few hours left to my finals, currently surviving on coffee
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