If 6x^2+xy-cos(y)=10, what is dy/dx?
EJ: As you'll see, this equation has NOT been solved for y, and it would be quite difficult to solve it for y. therefore, to find the derivative dy/dx, use IMPLICIT DIFFERENTIATION.
Enclose your original equation in parentheses and apply the derivative operator (d/dx) to the whole thing. Differentiate term by term. Note that xy is a product, which means you MUST apply the product rule, while remembering that y is presumed to be a function of x.
EJ?
Thank you! Can you explain getting the derivative of the function? There are a lot of terms.
I can guide you thru the process. First, what is the derivative (with respect to x) of 6x^2?
12x
Right. Given that xy is a product, and that y is assumed to be a function of x, what is the derivative of xy? ( )( )+( )( )
(x)(dy/dx)+(y)(dx/dx)
Yes, very good. And dx/dx=?
what about -cos(y)?
dx/dx=1
First: dx/dx= 1. so your derivative of xy is therefore x(dy/dx)+y. OK?
yes
What is the derivative of -cos y? Recall that y is assumed to be a function of x, so we must use the Chain Rule and differentiate y. What do you recall about the derivative of cos x? (d/dx)(cos x) = ?
-sinx
Right, and so the derivative of -cos x is what?
sinx
Right. Now, knowing that y is supposedly a function of x, what is the derivative with respect to x of -cos y?
sinx (dy/dx)
That's great! right on target!
What's the derivative of 10?
perfect thank you! Then 10 goes to zero and i solve for dy/dx right?
That's right. Confident that you can finish up?
yes thank you so much
My great pleasure, EJ! "See" you again on Open Study.
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