Question

A block is projected along a frictionless inclined plane at an angle of 32 degrees with an initial speed of 3.5m/s. How far up the plane does the block go?

Answer 1

could this be the diagram to represent the whole story?

Answer 2

Can you use tan32 to find the slope?

Answer 3

That way you have the total distance right?

Answer 4

And you know the accleration of the block is mg

Answer 5

Then... you could probably use the formula v^2=u^2+2as?

Answer 6

ya, I said in my working gsine32 = a= \[9.8x0.59=5.19\]

after that used \[v ^{2} = u ^{2}-2as= 3.5^{2}-2x5.19 s.\]

Answer 7

yay! So our thinking was along the same lines.. again :P But what do you do after that?

Answer 8

\[s = \frac{ -3.5^{2} }{ -5.19 } = 2.36\]

Answer 9

Is that the answer?

Answer 10

This is the one I came up with, I think it go as much as 2.36m???

Answer 11

I didn't understand how you found the time...

Answer 12

oh, S is for displacement in the text that I am using, sorry about that man

Answer 13

Woman* Oh right.. I thought it was seconds.. oops

Answer 14

The Free body diagram looks right.. Why'd you ask this question when you already know the answer though? :P

Answer 15

I am sorry I left wo- before man ha ha ha. I am revising alone, so with physics and mathematics you always underline a certain answer , even if it is wrong. So i have to ask. I think u understand what I am trying to say. And thanx for helping me.

Answer 16

I have no idea how I helped, but you're welcome :) Message if you have any more physics questions! They help me too!!

Answer 17

The fact that you were understanding my approach , and the direction of my working( of cause except for the s part), means that I was presenting the whole thing well. Let me say u were supporting?, Anyway, I will always mention you when I have a question, actually, let me close this one , and write the other one which I wasn't so sure of.