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Chemistry 12 Online
OpenStudy (anonymous):

Please help with this hofmann product.

OpenStudy (anonymous):

OpenStudy (anonymous):

@abb0t

OpenStudy (anonymous):

Idk what a hofmann product is....my prof didn't teach us that and its not in the book. So if someone helps I will love you !

OpenStudy (whpalmer4):

Maybe this will help? http://mhhe.com/physsci/chemistry/carey/student/olc/ch22hofmannelimination.html

OpenStudy (anonymous):

so a H and a group leave...how do i know which H leaves

OpenStudy (whpalmer4):

Maybe start reading here: https://en.wikipedia.org/wiki/Hofmann_elimination

OpenStudy (anonymous):

I did this. it said this

OpenStudy (anonymous):

OpenStudy (australopithecus):

E2 attacks is the removal of a hydrogen on the beta carbon antipariplanner to the hallogen atom

OpenStudy (australopithecus):

I was going to draw it out for you but Chmdraw is so prone to crashing :S

OpenStudy (anonymous):

so the carbon on the right

OpenStudy (australopithecus):

yes the carbon next to it

OpenStudy (australopithecus):

these electrons go into forming a pi bond and the halogen leaves with a lone pair of electrons

OpenStudy (anonymous):

so on the carbon on the left it will have a H and a CH3....while the carbon on the right will have CH3 and CH2CH3

OpenStudy (anonymous):

???

OpenStudy (anonymous):

bc thats how i drew it

OpenStudy (australopithecus):

Well you are left with either the cis or trans isomer

OpenStudy (australopithecus):

there is no chirality left

OpenStudy (anonymous):

it wants the major product

OpenStudy (australopithecus):

One second let me draw

OpenStudy (anonymous):

ok. thank you

OpenStudy (australopithecus):

The way you drew your final product is incorrect remember they are sp2 carbons btw

OpenStudy (anonymous):

so how should it look like?

OpenStudy (australopithecus):

Do you have a molecular modeling kit??

OpenStudy (anonymous):

no

OpenStudy (australopithecus):

you should get one

OpenStudy (anonymous):

I'm not a chem major...im a bio major....i just have to take chem....and he didnt teach this stuff :'(

OpenStudy (australopithecus):

They help a ton with stereochemistry, if you had one you could just build the molecule remove the two atoms and have your final structure

OpenStudy (anonymous):

i never thought i would need one in my life...

OpenStudy (australopithecus):

Most chem profs advise buying one at least that is what I though, visualizing stereochemistry can be tough for some people, ok chemdraw keeps crashing on me I will get it this time one second

OpenStudy (anonymous):

he never told us to get one.....he said to visualize it

OpenStudy (anonymous):

but he didn't cover this stuff

OpenStudy (anonymous):

he usually gives us easy compounds

OpenStudy (anonymous):

could u draw it on paper and put a pic up instead

OpenStudy (australopithecus):

Yeah even some chem profs can't visualize stereochemistry so bleh, although tbh this stuff isnt that tough to visualize. Look at this drawing and tell me if you can see why the product is what it is, remember there is no rotation around a pi bond (well there can be but you know, it is very high energy for it to occur). http://i.imgur.com/XgVfWwj.png

OpenStudy (australopithecus):

That is the transition state in the middle and those dashed linds represent partial bonds

OpenStudy (australopithecus):

Do you see why the product is what it is?

OpenStudy (australopithecus):

you need to rotate it in your head kind of

OpenStudy (anonymous):

i get how the pic works....but i still have no idea what to do with mine...

OpenStudy (australopithecus):

yours is the same deal

OpenStudy (anonymous):

OpenStudy (australopithecus):

You cant draw it like that, the bonds have specific angles

OpenStudy (australopithecus):

Draw it like I have it

OpenStudy (anonymous):

OpenStudy (anonymous):

better?

OpenStudy (australopithecus):

and get a molecular modeling kit if you are doing stereochemistry, or get software maybe even bring it into your exams

OpenStudy (australopithecus):

Yes A million times better

OpenStudy (anonymous):

still says its wrong

OpenStudy (australopithecus):

What happened to your methyl group

OpenStudy (anonymous):

methyl group?

OpenStudy (australopithecus):

CH3

OpenStudy (australopithecus):

Look at your molecule

OpenStudy (anonymous):

do i have to retricethe H to the carbons

OpenStudy (anonymous):

add*

OpenStudy (australopithecus):

Huh? It is a simple E2 reaction same one as I drew

OpenStudy (australopithecus):

B: is a sterically hindered base btw

OpenStudy (anonymous):

you said i was missing a methyl group

OpenStudy (australopithecus):

Look at your reactants and products

OpenStudy (australopithecus):

or rather product

OpenStudy (australopithecus):

Do you have the same number of carbons?

OpenStudy (australopithecus):

Remember in this reaction you are only losing a Hydrogen and a halide

OpenStudy (australopithecus):

from your reactant

OpenStudy (anonymous):

yes. I have the same number of Carbons

OpenStudy (australopithecus):

No you dont

OpenStudy (australopithecus):

I count 6 on your reactant and 4 on your product

OpenStudy (australopithecus):

Look at the reaction I posted it is the same one as the question

OpenStudy (australopithecus):

being asked

OpenStudy (australopithecus):

draw the arrows if you have to

OpenStudy (australopithecus):

Do you understand skeleton structures?

OpenStudy (australopithecus):

If not I can explain

OpenStudy (anonymous):

yea. i still don't get how you see 4 carbons? could u draw it using the drawing thing on here?

OpenStudy (australopithecus):

Please get use to this representation it is fundamental to your success. http://i.imgur.com/FCknGBx.png

OpenStudy (australopithecus):

That hydrogen I drew on there doesnt need to be represented, I just drew it there because it is of interest to the reaction you are performing on that molecule

OpenStudy (australopithecus):

http://i.imgur.com/OPbtmnM.png so really this

OpenStudy (anonymous):

OpenStudy (anonymous):

bc the Cl leaves

OpenStudy (australopithecus):

You added a methyl group

OpenStudy (australopithecus):

COunt your carbons damit

OpenStudy (anonymous):

so I changed the methyl group to a H. I have 6 carbon atoms

OpenStudy (australopithecus):

right

OpenStudy (australopithecus):

but where did you place the H it matters

OpenStudy (anonymous):

OpenStudy (australopithecus):

Yup good job

OpenStudy (anonymous):

but it said this one was wrong

OpenStudy (australopithecus):

Hmm one second

OpenStudy (australopithecus):

Actually keep the stereochemistry in sorry

OpenStudy (australopithecus):

I hated that website when I used it

OpenStudy (australopithecus):

you would post the correct answer and it would still shaft you

OpenStudy (australopithecus):

http://i.imgur.com/vRbwZw2.png

OpenStudy (australopithecus):

Like this

OpenStudy (anonymous):

so two groups at the back and two in the front

OpenStudy (australopithecus):

so, http://chemwiki.ucdavis.edu/%40api/deki/files/2271/Untitled-1.jpg

OpenStudy (australopithecus):

like that

OpenStudy (anonymous):

OpenStudy (anonymous):

like that

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