E2 attacks is the removal of a hydrogen on the beta carbon antipariplanner to the hallogen atom
OpenStudy (australopithecus):
I was going to draw it out for you but Chmdraw is so prone to crashing :S
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OpenStudy (anonymous):
so the carbon on the right
OpenStudy (australopithecus):
yes the carbon next to it
OpenStudy (australopithecus):
these electrons go into forming a pi bond and the halogen leaves with a lone pair of electrons
OpenStudy (anonymous):
so on the carbon on the left it will have a H and a CH3....while the carbon on the right will have CH3 and CH2CH3
OpenStudy (anonymous):
???
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OpenStudy (anonymous):
bc thats how i drew it
OpenStudy (australopithecus):
Well you are left with either the cis or trans isomer
OpenStudy (australopithecus):
there is no chirality left
OpenStudy (anonymous):
it wants the major product
OpenStudy (australopithecus):
One second let me draw
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OpenStudy (anonymous):
ok. thank you
OpenStudy (australopithecus):
The way you drew your final product is incorrect remember they are sp2 carbons btw
OpenStudy (anonymous):
so how should it look like?
OpenStudy (australopithecus):
Do you have a molecular modeling kit??
OpenStudy (anonymous):
no
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OpenStudy (australopithecus):
you should get one
OpenStudy (anonymous):
I'm not a chem major...im a bio major....i just have to take chem....and he didnt teach this stuff :'(
OpenStudy (australopithecus):
They help a ton with stereochemistry, if you had one you could just build the molecule remove the two atoms and have your final structure
OpenStudy (anonymous):
i never thought i would need one in my life...
OpenStudy (australopithecus):
Most chem profs advise buying one at least that is what I though, visualizing stereochemistry can be tough for some people, ok chemdraw keeps crashing on me I will get it this time one second
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OpenStudy (anonymous):
he never told us to get one.....he said to visualize it
OpenStudy (anonymous):
but he didn't cover this stuff
OpenStudy (anonymous):
he usually gives us easy compounds
OpenStudy (anonymous):
could u draw it on paper and put a pic up instead
OpenStudy (australopithecus):
Yeah even some chem profs can't visualize stereochemistry so bleh, although tbh this stuff isnt that tough to visualize.
Look at this drawing and tell me if you can see why the product is what it is, remember there is no rotation around a pi bond (well there can be but you know, it is very high energy for it to occur).
http://i.imgur.com/XgVfWwj.png
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OpenStudy (australopithecus):
That is the transition state in the middle and those dashed linds represent partial bonds
OpenStudy (australopithecus):
Do you see why the product is what it is?
OpenStudy (australopithecus):
you need to rotate it in your head kind of
OpenStudy (anonymous):
i get how the pic works....but i still have no idea what to do with mine...
OpenStudy (australopithecus):
yours is the same deal
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OpenStudy (anonymous):
OpenStudy (australopithecus):
You cant draw it like that, the bonds have specific angles
OpenStudy (australopithecus):
Draw it like I have it
OpenStudy (anonymous):
OpenStudy (anonymous):
better?
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OpenStudy (australopithecus):
and get a molecular modeling kit if you are doing stereochemistry, or get software maybe even bring it into your exams
OpenStudy (australopithecus):
Yes A million times better
OpenStudy (anonymous):
still says its wrong
OpenStudy (australopithecus):
What happened to your methyl group
OpenStudy (anonymous):
methyl group?
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OpenStudy (australopithecus):
CH3
OpenStudy (australopithecus):
Look at your molecule
OpenStudy (anonymous):
do i have to retricethe H to the carbons
OpenStudy (anonymous):
add*
OpenStudy (australopithecus):
Huh? It is a simple E2 reaction same one as I drew
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OpenStudy (australopithecus):
B: is a sterically hindered base btw
OpenStudy (anonymous):
you said i was missing a methyl group
OpenStudy (australopithecus):
Look at your reactants and products
OpenStudy (australopithecus):
or rather product
OpenStudy (australopithecus):
Do you have the same number of carbons?
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OpenStudy (australopithecus):
Remember in this reaction you are only losing a Hydrogen and a halide
OpenStudy (australopithecus):
from your reactant
OpenStudy (anonymous):
yes. I have the same number of Carbons
OpenStudy (australopithecus):
No you dont
OpenStudy (australopithecus):
I count 6 on your reactant and 4 on your product
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OpenStudy (australopithecus):
Look at the reaction I posted it is the same one as the question
OpenStudy (australopithecus):
being asked
OpenStudy (australopithecus):
draw the arrows if you have to
OpenStudy (australopithecus):
Do you understand skeleton structures?
OpenStudy (australopithecus):
If not I can explain
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OpenStudy (anonymous):
yea. i still don't get how you see 4 carbons? could u draw it using the drawing thing on here?
That hydrogen I drew on there doesnt need to be represented, I just drew it there because it is of interest to the reaction you are performing on that molecule