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Mathematics 17 Online
OpenStudy (anonymous):

2. Some investments in the stock market have earned 10% annually. The total value of the investment, A, at this rate can be found using A=P(1.10)^n, where P is the initial value of the investment, and n is the number of years the money is invested. If $1,000 is invested in the stock market at this annual rate of return, what is the expected total value after 18 years?? A.$ 4,054.47 B.$ 5,559.92 C.$ 18,700.00 D.$ 19,800.00

OpenStudy (whpalmer4):

\[P=1000\]\[n=18\]\[A=P(1.10)^n = 1000(1.10)^{18} =\] A hint for working this one in your head: a 10% rate of return doubles your money after about 7 periods. (\(1.1^7\approx 1.95\))

OpenStudy (anonymous):

so would i just multiply 1000(1.10)^18 ? @whpalmer4

OpenStudy (whpalmer4):

Yep, it's a simple "plug-n-chug" problem...

OpenStudy (whpalmer4):

Remember the operator precedence: you do 1.10^18 first, then multiply it by 1000.

OpenStudy (whpalmer4):

It would be nice if it worked the other way, as your investment would then be worth $5559917313492231481000000000000000000000000000000000000 :-)

OpenStudy (anonymous):

lol so i did that and i got something like 72,225,966.051 ... is that right or in the right direction

OpenStudy (whpalmer4):

No, the correct answer is among your answer choices. What do you get for 1.10^18?

OpenStudy (anonymous):

oohhh lol nevermind i punched the numbers in wrong my bad is it B? because thats what i got

OpenStudy (whpalmer4):

B is correct.

OpenStudy (anonymous):

yes finally lol thank you so much

OpenStudy (whpalmer4):

Working from my "back of the envelope" hint: if we double every 7 years, we've got 2 complete doublings (1000->2000->4000) plus about half of another doubling, and B is the only answer nearby.

OpenStudy (anonymous):

okay i see, thanks

OpenStudy (whpalmer4):

always good to be able to do a sanity check estimate on your answers...

OpenStudy (anonymous):

you're right lol

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