If the average of four numbers is 22, and three of the numbers are 7, 11, and 18, then what is the fourth number?
52 because 52+11+7+18= 88 and 88 divided by 4 = 22
average = (sum of all the numbers) / (count of the numbers...how many there are). Here we know the average is 22, and we know 3 of the 4 numbers, so we represent the fourth number by x. Add up the four numbers. Sum of the numbers is: ???? How many numbers are there? ???? Divde the sum by the count. Equate the result to the average (22). How would you now solve for x?
Isaiah, why the x in the denom.?
Isn't the average = to 22?
\[\frac{1}{4} (x+18+11+7)=22 \]x = 52
Nice work, Robert. But you might want to lead Megan through the steps involved here.
\[\frac{ 7+11+18+x }{ 4 }=22\]
Again, right on. But how do you solve this equation for x? Megan may want to know.
(For jagatuba only: Thanks for referring me to Preetha a week or so ago. I did contact her and find her to be very helpful!)
@megan177 The average of n numbers is the sum of the n numbers divided by n.
\[36+x=22\times4\] \[x=88-36\]
Right on. But what about the algebraic steps involved in solving that equation for x?
Cool, Jag! Megan, how are you doing?
@mathmale YW. Glad she could help.
Thanks. Megan? Still with us?
@megan177 ?
Megan is "off line"
relax I was off line, my computer froze. okay I get it now, thanks guys
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