Question

Lea drives from Manayunk to Wilmington at 2/3 of the average speed at which she returned from Wilmington to Manayunk. What percent of her total driving time did it take Lea to drive from Manayunk to Wilmington?

Answer 1

try using the d=rt formula
d = distance r = rate t = time

Answer 2

okay one sec... and that was the formula i couldn't remember... I'll try it out

Answer 3

Okay :)

Answer 4

well what would be the distance? cause the rate is 2/3?

Answer 5

or what would be the time?

Answer 6

Is is one of those tricky question, does if have answer choices? (Just curious).

Answer 7

*This

Answer 8

yes it does, hold on, I will post them.

Answer 9

since the total driving time is not giving, it would be difficult to know. Maybe there's a method need to be used to know the time first and use the d=rt formula

Answer 10

A) 33(1/3)%
B) 40%
C) 50%
D) 60%
E) 66(2/3)%

Answer 11

@Mertsj

Answer 12

hmm idk would time be 1/60 idk, haha

Answer 13

Hmm,
I think Zale is on the right track, you most definitely use \(d=rt\).

Answer 14

but what would be the time, that is all I need I think... cause I think the rate would be 2/3

Answer 15

Possible we use direct variation?
\(y=kx\)
So:
\(d=(\dfrac{2}{3})t\)

\(k=\dfrac{y}{x}\)

\(\dfrac{2}{3}=\dfrac{y}{x}\)

I guess we could try the multiple choice from there? I don't know >.<

Answer 16

no that is not enough information

Answer 17

I know :-P.
I was just attempting it, hopefully Mertsj can explain it.