Question

Trevor is tiling his bathroom floor, which has an area that is represented as 120r3 square inches. Each tile has an area of square root of the quantity 16 r to the ninth power. The total number of tiles used can be represented by the expression below.
one hundred twenty r to the third power, all over the square root of the quantity sixteen r to the ninth power

Answer 1

\[120r^{3} = \sqrt{16r^{9}}\]
Is that the equation?

Answer 2

\[\frac{ 120r^2}{ \sqrt{16r^9}}\]

Answer 3

oh! okay

\[\frac{ 120r^{3} }{ \sqrt{16r^{9}} } = \frac{ 120r^{3} }{ 16^{1/2}r^{9/2} }\]

Wait, is it 120r^2, or 120r^3

Answer 4

Its 120^2

Answer 5

okay,
\[\frac{ 120r^{2} }{ \sqrt{16r^{9}} } = \frac{ 120r^{2} }{4r^\frac{ 9 }{ 2 } }\]

Answer 6

I don't know what you did here

Answer 7

\[\sqrt{16} = 4\]
right? Well i just took that out
also...
\[\sqrt[n]{x^{m}} = x^{\frac{ m }{ n }}\]
and since...
\[\sqrt{x} = \sqrt[2]{x}\]
\[\sqrt{r^{9}} = r^{\frac{ 9 }{ 2 }}\]
see?

Answer 8

Okay... I got 30... But when I look around I see 7.5. Which is right?

Answer 9

it's 30 but don't forget about the r

Answer 10

Don't the r's cancel out?

Answer 11

@april115 Can you help with this? Please?

Answer 12

@Agent47 Help?

Answer 13

@adrynicoleb Can you PLEASEE help!?

Answer 14

Ok. I'll see what I can do.

Answer 15

Thank you SOO much!

Answer 16

But I'm warning you, I am not that good at math. ._.

Answer 17

I'm not either. (:

Answer 18

Lol yeah. I don't know. *bows head in shame*

Answer 19

.... Uh. This is so hard!

Answer 20

\[\frac{ 120r^{2} }{ 4r^{9/2} } = \frac{ 30r^{2} }{ r^{9/2} } = \frac{ 30r^{2} }{ \sqrt{r^{9}} }\]
\[\frac{ 30r^{2} }{ \sqrt{r^{9}}} * \frac{ \sqrt{r^{9}} }{\sqrt{r^{9}} } = \frac{ 30r^{2}\sqrt{r^{9}} }{ r^{9} }\]
\[= 30^{-7}\sqrt{r^9}\]