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Mathematics 13 Online
OpenStudy (anonymous):

Will fan and give medal! Attachment in comments Not so sure on my answers.

OpenStudy (anonymous):

OpenStudy (mathmale):

Your response to #1 is fine. But I'd be much more interested in seeing the work you did that led to your three answers.

OpenStudy (anonymous):

b,c,d

OpenStudy (mathmale):

CF: Here's what I'm looking for in terms of your own work: In Problem #1, we first need to find the slope of the tangent line to the circle x^2 + y^2 = 29 at the point (2,5). Recall that the derivative produces a formula for the slope of the tangent line. Using implicit differentiation, find dy/dx of x^2 + y^ 2 = 29. It is dy/dx = -x/y. Let me know if you need more discussion of this process. Then at the point (2,5), the slope of the tangent line is -x/y, or -2/5. Notice that all of the four choices of answers have this same slope. Last, substitute this slope and the coordinates of the given point (2,5) into the point-slop equation of a straight line: \[y-y _{0}=m _{TL}(x-x _{0}).\] y-5+(-2/5) (x-2). Your slope, m, is -2/5. The point in question is (2,5). Which of the four answer options is the correct one? Does this discussion help? If it's not entirely clear, please ask specific questions.

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