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Find all values of α on the interval [0,2π) satisfying the equation tanαsinα+√3 sinα =0
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First you need to factor the equation.
ok so we will factor out sinα right
Correct and and we would have (sinex) (tanx+\[Correct we would then have (sine x) (tanx +\sqrt{3)}=0\]
yes
Solve for each.
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so it will be sinx =0 and ( tans x+sqrt 3) =0and solve them individually
so for sinx the solutions are 0 and pie right
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