Wats the derivative of pi^2?

Question

anonymous · Answer

I typed 2pi but its not working!!!!!!!!!!!!!?????????

kainui · Answer

Must be some kind of error in the back of the book, this is clearly the right answer.

$$\lim_{h \rightarrow 0}\frac{ (\pi+h)^2 -h^2}{ h }=2\pi$$

I just checked with the definition and everything.

anonymous · Answer

yeah ur rite thxxx!!!!!

anonymous · Answer

derivative of pi^2 is 2pi . correct

anonymous · Answer

Yeah it's definitely an error. 2pi is correct

anonymous · Answer

u guys r the best!!!! if u hav a kik i'll mesege u my name! ;)

ranga · Answer

Isn't the derivative of a constant zero?

lncognlto · Answer

The derivative of pi^2 would indeed be 2pi. :)

anonymous · Answer

oh r u sure ranga? thts not wat my prof said the other day

lncognlto · Answer

@Ranga, are you sure the rules of constants apply to Pi?

superdavesuper · Answer

wait wait wait @kainui Pi is a constant so its derivative should be zero right?

superdavesuper · Answer

I agree w @ranga on this one :)

ranga · Answer

pi is a number, an irrational number.  It is not a variable.  The derivative of a constant is zero.

kainui · Answer

@superdavesuper Incorrect. Since 2pi is periodic, just like the derivative of a constant of 0, it's exactly the same as if you go 2pi, 4pi, etc...

anonymous · Answer

I agree with @incognito @AustinC  @Kainui  The derivative of pi^2 would be 2pi

anonymous · Answer

Yeah like troy and them said pi^2 is definitely 2pi

anonymous · Answer

ty so much! 2pi for sure. I'll call my friends to tell them tha anser is rong in the bak of the book. :) :) :)

anonymous · Answer

$\large    \lim \limits_{h \rightarrow 0}\frac{ \pi^2 -\pi^2}{ h }= 0$

ranga · Answer

what is the answer in the back of the book?

anonymous · Answer

@janaki.t23 u forgot the h in the top part thats y ur getin the rong answer.

anonymous · Answer

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