Question

An 85 g piece of aluminum (C = 0.217 cal/gC°) at 98°C is placed on top of a large block of ice at 0°C. Determine the mass of ice that melts.

Answer 1

@Vincent-Lyon.Fr

Answer 2

Compare the heat removed from the aluminium block as it goes from 98 °C to 0 °C and that needed to melt a mass m of ice.

Answer 3

you mean the final temp. of aluminum is 0 degree C?

Answer 4

Yes, since the block of ice is as large as you need.

Answer 5

okay..
the formula I used is -Qlost=Qgained by ice

Qlost by Al = (Mass)(Spec.heat)(change in temp)
Qgainedby ice= (mass)(spec.heat)(change in temp)

-(mass of Al)(SH)(CHange temp)= (mass of ice)(SHof ice)(change in temp)
to get
mass of ice= -(mass of Al)(SH of Al)(change in temp) / (mass of ice)(Spec. heat of ice)

am i right?

Answer 6

i mean:
all over (spec. heat of ice) * (change in temp by ice)

:D

Answer 7

No, the ice does not undergo a change in temperature, it undergoes a change of state.
You must use the latent heat of fusion of ice to do your calculation.

Answer 8

You should end up with about 23 g of melted ice.

Answer 9

right, THANKS!! :)