Question

Henry rolls 2 number cubes numbered 1 through 6 while playing his favorite board game. He will get a second turn if he rolls a sum that is an even number less than 10.

What are Henry's chances of getting a second turn when he rolls the number cubes?
@ganeshie8

Answer 1

start by calculating how many ways Henry can get an 'even sum'

Answer 2

2,4,6,8,

Answer 3

yes, when he adds the numbers on both cubes, he should get one of them

Answer 4

actually we done even need to do all that calculation.
just see that, there are exactly 3 even numbers and 3 odd numbers between 1 and 6

Answer 5

so, the chances of getting an even sum is exactly 1/2

Answer 6

see if that makes more or less sense

Answer 7

7/18 @ganeshie8

Answer 8

how did u get 7/18 ?

Answer 9

i dont know either lol how do we figure this out?

Answer 10

if you do the actual calculation you will get 18/36 = 1/2

Answer 11

are you sure its not 17/36

Answer 12

let me think a bit

Answer 13

oh we missed this constraint :-
less than 10.

Answer 14

5/36

Answer 15

lets do this properly :-

if he gets \(1\) on first die, then he can get \(1, 3, 5\) on second die : 3 ways
if he gets \(3\) on first die, then he can get \(1, 3, 5\) on second die : 3 ways
if he gets \(5\) on first die, then he can get \(1, 3, 5\) on second die : 3 ways

if he gets \(2\) on first die, then he can get \(2, 4, 6\) on second die : 3 ways
if he gets \(4\) on first die, then he can get \(2, 4\) on second die : 2 ways
if he gets \(6\) on first die, then he can get \(2\) on second die : 1 ways

add them all up

Answer 16

total ways it can be an even sum = 3+3+3+3+2+1 = 15

Answer 17

15

Answer 18

so the chances are 15/36 = 5/12

Answer 19

u have that in ur options ha ?

Answer 20

These are the options
7/18
11/18
5/36
17/36

Answer 21

if he gets 1 on first die, then he can get 1,3,5 on second die : 3 ways
if he gets 3 on first die, then he can get 1,3,5 on second die : 3 ways
if he gets 5 on first die, then he can get 1,3 on second die : 2 ways

if he gets 2 on first die, then he can get 2,4,6 on second die : 3 ways
if he gets 4 on first die, then he can get 2,4 on second die : 2 ways
if he gets 6 on first die, then he can get 2 on second die : 1 ways

Now add themm up. and do double check if we counted all the possible ways ok

Answer 22

14

Answer 23

yes 14 is the # of ways he can get an even sum
divide it by total number ways he can roll the die : 36

Answer 24

7/18

Answer 25

Thank You!

Answer 26

thats right ! do double check if we missed counting any... seems my brain is dead today lol :o

Answer 27

no its not its bright as usual.

Answer 28

lol no, ur brain is bright, u caught my mistakes xD