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Mathematics 9 Online
OpenStudy (anonymous):

How do you use methods of an indirect proof to determine whether a short proof is logically valid?

OpenStudy (perl):

do you have an example

OpenStudy (perl):

you can use proof by contradiction assume the negation of your claim , show that this leads to a contradiction. so your claim must be true.

OpenStudy (anonymous):

well not really but the lesson is on indirect proofs

OpenStudy (perl):

for example : Claim: sqrt(2) is irrational proof : assume sqrt(2) is rational (negation of the original claim) we can show that a contradiction follows if sqrt(2) = p/q

OpenStudy (anonymous):

can you give me another example ?

OpenStudy (perl):

lets do an easier proof. since that one is kind of hard claim : if n is even then n^2 is even.

OpenStudy (perl):

Indirect Proof: Assume what you need to prove is false, and then show that something contradictory (absurd) happens.

OpenStudy (anonymous):

ok thanks a lot

OpenStudy (anonymous):

yes ?

OpenStudy (perl):

ok so assume the claim above is false. ie, it is false that ' if n is even then n^2 is even'. This is a little harder to negate than the last example. How do you negate a conditional? Negating p->q is p and not q. This means that n is even and n^2 is not even (odd). From this can we produce a contradiction?

OpenStudy (anonymous):

cant you say if n^2 is odd then n has to be even ?

OpenStudy (perl):

well we are given that n is even and n^2 is odd by negating our original statement. actually if n^2 is odd then n is odd. but that is harder to prove. how about this, if n is even, then n = 2k, then n^2 = 4k^2, so n^2 is even. but we assumed that n^2 is odd. contradiction

OpenStudy (anonymous):

ok give me a moment

OpenStudy (anonymous):

i honestly dont have a clue

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