Question

guys how to solve this (tan^3)x
help me guys with solution :(

Answer 1

theres no equation?

Answer 2

oh imean integrate of (tan^3)x

Answer 3

You know that tan²x=sec²x−1.
Also d(tanx)/dx=sec²x, you you may get something. Lets try it out.

∫tan³x dx= ∫tan²x tanx dx
=∫(sec²x−1)tanx dx
=∫sec²xtanx dx − ∫tanx dx
Put u=tanx, then du/dx=sec²x, du=sec²xdx
=∫u du − ∫tanx dx
=u²/2 − log|secx| + C
=(tan²x)/2 − log|secx| + C

Answer 4

from yahoo

Answer 5

do you think is that a correct?

Answer 6

yeah it is see: http://ocw.mit.edu/courses/mathematics/18-01sc-single-variable-calculus-fall-2010/unit-4-techniques-of-integration/part-a-trigonometric-powers-trigonometric-substitution-and-completing-the-square/session-71-integrals-involving-secant-cosecant-and-cotangent/MIT18_01SCF10_ex71sol.pdf

Answer 7

oh i see.. thank you so much

Answer 8

Wait, why are you doing integration? I don't see anything about integration being asked here. Lol