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Physics 21 Online
OpenStudy (anonymous):

what does acceleration do to the speed of an object free falling?

OpenStudy (potatoes.ramu):

The acceleration is directly proportional to the velocity :)

OpenStudy (anonymous):

acceleration increases the speed of the freely falling object

OpenStudy (anonymous):

Mathematically, we define velocity as the change in position overtime - that is - the first derivate of coordinates with respect to time. \[v = \frac{ dx }{ dt } \] Acceleration is the change of the speed at which an object is travelling - that is - the first derivative of velocity with respect to time. \[a = \frac{ dv }{ dt } \] But we already said that velocity is a function of coordinates, so it turns out that acceleration is the second derivative of coordinates over time. \[v = \frac{ d^2x }{ dt^2 } \] We can generalize the definition as \[a = \frac{ dv }{ dt } = \frac{ v - v _{0} }{ \Delta t }\] and solving for v gives the law for motion \[v = v _{0}+a* t\] So, the answer to your question - when there is an increase in acceleration, there is an increase in velocity. For a free-falling object, acceleration causes it to fall quicker and quicker as it falls according to the equation (initial velocity is zero as it is free-fall motion) \[v = a*t\]

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