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Evaluate the logarithm
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\[\log _{4} 1024\]
A. 5 B. -5 C. 4 D. 6
A. 5 is the answer \[4^x =1024\] x=5
$$ \log_41024=y\\ \implies 1024=4^y\\ \log_2 1024=\log_2 4^y=y~\log_2 4\\ y=\cfrac{\log_2 1024}{\log_2 4}=\cfrac{10}{2}=5 $$ Where \(log_2 x\) is the log is base of 2 of \(x\). I used base 2 for this converstion because I noticed that 1024 and 4 are easily represented by \(2^x\) for some \(x\). Use natural logs if \(e\) is involved or base 10 is numbers are in powers of 10, such as 1 000, or 1 000 000. Therefore, $$ \log_4 1024=5 $$ http://www.wolframalpha.com/input/?i=log+base+4+1024
THnks
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