Question

-10(1/2x-1/5y)+30(1/6x+4/5y) how do I simplify this

Answer 1

\(\bf -10\left(\cfrac{1}{2x}-\cfrac{1}{5y}\right)+30\left(\cfrac{1}{6x}-\cfrac{4}{5y}\right)\quad ?\)

Answer 2

\(\bf -10\left(\cfrac{1}{2}x-\cfrac{1}{5}y\right)+30\left(\cfrac{1}{6}x-\cfrac{4}{5}y\right)\quad ?\)

Answer 3

first off you'd need to distribute, of course

Answer 4

Yes the 2nd one is correct

Answer 5

\(\bf -10\left(\cfrac{1}{2}x-\cfrac{1}{5}y\right)+30\left(\cfrac{1}{6}x-\cfrac{4}{5}y\right)\implies

{\color{red}{ -10}}\left(\cfrac{x}{2}-\cfrac{y}{5}\right)+{\color{red}{ 30}}\left(\cfrac{x}{6}-\cfrac{4y}{5}\right)\\ \quad \\

\left(\cfrac{{\color{red}{ -10}}x}{2}-\cfrac{{\color{red}{ -10}}y}{5}\right)+\left(\cfrac{{\color{red}{ 30}}x}{6}-\cfrac{{\color{red}{ 30}}\cdot 4y}{5}\right)\)

see what you can cancel out from the denominator

Answer 6

hmmm shoot ... got a bit truncated... ok so

\(\bf -10\left(\cfrac{1}{2}x-\cfrac{1}{5}y\right)+30\left(\cfrac{1}{6}x-\cfrac{4}{5}y\right)\\ \quad \\\implies

{\color{red}{ -10}}\left(\cfrac{x}{2}-\cfrac{y}{5}\right)+{\color{red}{ 30}}\left(\cfrac{x}{6}-\cfrac{4y}{5}\right)\\ \quad \\

\left(\cfrac{{\color{red}{ -10}}x}{2}-\cfrac{{\color{red}{ -10}}y}{5}\right)+\left(\cfrac{{\color{red}{ 30}}x}{6}-\cfrac{{\color{red}{ 30}}\cdot 4y}{5}\right)\)

Answer 7

see any thing we can cancel out in the denominator?

Answer 8

Ty for helping

Answer 9

yw