Question

Correlation and Causation

Answer 1

?

Answer 2

could you help?

Answer 3

No, sorry. This is not my strong part.

Answer 4

ok thanx anyway

Answer 5

@Indivicivet @mathmale , maybe you guys can?

Answer 6

@oldrin.bataku

Answer 7

Regarding that table: I see that the data is NOT linear. Try graphing it to see this visually. Therefore, the linear correlation is very low. I'd vote for r = -0.04.

Answer 8

What about part B and C @mathmale

Answer 9

Part B is MUCH easier; you need only calculate a slope. Remember the formula for the slope of a straight line?
Part C: Don't know, because no graph appears for Part C.

Answer 10

ok so for part B which number do i use? @mathmale

Answer 11

Please look carefully at the table. You are given a number of points on the graph of the velocity versus time graph.

Focus on the first two columns: If t=10, velocity=0.2; if t=20, velocity=0.8. In other words, your points are (10,0.2) and (20,0.8). Please find the slope of the line connecting those two points.

Answer 12

I got 0.510416666667 @mathmale

Answer 13

I also got 0.490384615385 when I added them

Answer 14

Could you help @wolf1728

Answer 15

Baby: Please, show me your work. Also, please type out or write for me the formula for slope that you're using.

Answer 16

y^2-Y^1/x^2-X^1

Answer 17

that's fine. you should get\[\frac{ 0.8-0.2 }{ 20-10}=m.\]
Find m. (It's not 0.51).
I strongly suggest that you use plenty of parentheses if you're trying to do this on your calculator. (0.8-0.2) / (20-10) !!!

Answer 18

0.06 @mathmale

Answer 19

Cool. There you go!

Answer 20

do you know what the slope represents

Answer 21

Part C: Unfortunately, there's no graph to look at, so I can't be of much help there.

You do need to understand the meaning of "slope of a line," so I'd strongly suggest that you do an internet search for that definition and examples. I know what it means; it's essential that you do also.

Answer 22

ok

Answer 23

thanks for the medal!

Here's one example of the rich resources available online:

http://www.purplemath.com/modules/slope.htm