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Chemistry 21 Online
OpenStudy (anonymous):

can someone help me pls? is the following reaction correct: http://puu.sh/6iM99.png

OpenStudy (wolfe8):

What is this reaction supposed to be?

OpenStudy (anonymous):

I dont know I set it up myself since the red substances are each others conjugate base pairs, therefore I figured I could take the base and add a proton from water to form its conjugate acid & OH-

OpenStudy (wolfe8):

Hmm I'm not sure I can help you. I kind of know the terms but I don't really remember anymore. Sorry. Good luck.

OpenStudy (anonymous):

ok thank you anyways :)

OpenStudy (anonymous):

Ions are solvated in water solution - that is - they're surrounded by water molecules. The latter are dipoles - they have a partial positive charge at the Hydrogens and a partial negative charge at the Oxygen atom. Sodium cations are solvated, interacting with the Oxygen atom of a few water molecules, so its positive charge is cancelled. Similarly, Hydroxide anions interact to cancel out their negative charge. As a result, electrostatic interaction between the charges of the ions is impossible and they float freely in the solution. It is incorrect to write such a complex containing an OH group as it would mean that there would be a neutral particle with the structure NaOH in the solution, which is impossible. The moment water gets in touch with such a structure, it would dissolve it by solvating the ions. Solvation is a physicochemical process which means that it has some properties typical of chemical reactions. There is heat taken in or released as a result of solvation. It is the driving force that causes some compounds to dissolve and others to precipitate.

OpenStudy (vincent-lyon.fr):

This reaction would simply be written : Na(OH)(s) --> Na+(aq) + OH–(aq) Na(OH)(aq) does not exist.

OpenStudy (anonymous):

ok thank you for the help! I knew something was wrong in that reaction.

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