Question

solve In 2+ In x= 5 I don't understand please help WILL GIVE MEDALS

Answer 1

There are 3 important rules for logs in problems such as this one.
ln a + ln b = ln (ab)
ln a - ln b + ln (a/b)
b*ln a = ln (a^b)

May I assume you're familiar with these?

If so, which one applies to the problem you've posted?

Answer 2

the first one

Answer 3

@mathmale

Answer 4

OK. Right. If ln a + ln b = ln (ab),
then ln 2 + ln 5 = ln (???)

Answer 5

How are you doing with this problem so far, DMB?

Answer 6

DMB: I surely would have liked to have helped you to find the solution to this problem. Next time, please let me know before you log off.

Answer 7

ln 2 + ln x = 5. Per the rules of log we convert to ln (2x) = 5. Now you must expointiate the log. Since it is a natural log we use e.

e^ln(2x) = e^5. This will give you 2x = e^5. Solve from there.

Answer 8

@mathmale I think he was kicked out of the net so that he logged off without warning you.

Answer 9

Hey @mathmale sorry got kick off and then had to go to tennis practice

Answer 10

@nelsonjedi how do i solve that

Answer 11

is that the answer?

Answer 12

yes
but it is 2x
so divide by 2

Answer 13

how do you do that

Answer 14

\[\log_{b} A +\log_{b} D =\log_{b} AD \]

Answer 15

\[\ln x =\log_{e} x\]
\[\log_{e} x+\log_{e} 2 =5\rightarrow \log_{e} 2x =5 \rightarrow \log_{e} 2x=5\log_{e} e\]

Answer 16

\[\log_{e} 2x=\log_{e} e ^{5} \rightarrow 2x=e ^{5} \rightarrow x=\frac{ 1 }{ 2 }e ^{5}\]

Answer 17

so the answer is \[\frac{ 1 }{ 2 }e ^{5}\]

Answer 18

yes

Answer 19

understand now ?

Answer 20

yes thank you