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OpenStudy (anonymous):
Please Help! Medal Will Be Rewarded!!! Find y’ for y=xsin^2 x
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OpenStudy (cwrw238):
use the product rule
OpenStudy (anonymous):
@surjithayer
OpenStudy (anonymous):
Okay thank you
OpenStudy (anonymous):
\[y=x \sin ^{2}x,y'=x \left( 2\sin x \cos x \right)+1*\sin ^{2}x=x \sin 2x+\sin ^{2}x\]
OpenStudy (anonymous):
okay, thats something like what i got. I se what you did! Thank you so much!!!!
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OpenStudy (anonymous):
yw
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