carson drives to school the same way each day and there are two independent traffic lights on his trip to school. He knows that there is a 30% chance that he will have to stop at the first light and an 80% chance that he will have to stop at the second light. What is the probability that he will NOT have to stop at either light?

14%

24%

50%

80%

Question

carson drives to school the same way each day and there are two independent traffic lights on his trip to school. He knows that there is a 30% chance that he will have to stop at the first light and an 80% chance that he will have to stop at the second light. What is the probability that he will NOT have to stop at either light?

 14%

 24%

 50%

 80%

anonymous · Answer

Okay Yayo. So 30% and 80% chance that he will have to stop at one of the lights. So what we want to find is the difference of that percentage from 100% so we know the probability of him NOT having to stop.

anonymous · Answer

100 - 30 = 70% and 100-80 = 20%

anonymous · Answer

So let's multiply them together to find the probability. 7/10 * 1*5. What do you get?

anonymous · Answer

14%?

anonymous · Answer

A two-way frequency table shows grades for students in college and students in high school.

anonymous · Answer

Based on this data, are "being in high school" and "GPA above 3.0" independent events?
 Yes, P(high school | GPA above 3.0) = P(high school)

 Yes, P(high school | GPA above 3.0) = P(GPA above 3.0)

 No, P(high school | GPA above 3.0) ≠ P(high school)

 No, P(high school | GPA above 3.0) ≠ P(GPA above 3.0)

anonymous · Answer

@Lethal

anonymous · Answer

Sorry. Yes I'm back. It's 14% correct.

anonymous · Answer

For the second one. I'm not sure. Try posting it in a new question :)