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Find the sum of the geometric sequence. 1, 1/4, 1/16, 1/64, 1/256
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\[a \left( \frac{ 1-r ^{n} }{ 1-r } \right)\] a - first term in series r - common factor between sequence progression (in this case what each number decreases by) n - number of terms you want to add up
@nikato would i solve this like the last one?
yes. but use that formula^ becuz its geometric. and instead of finding the common difference, u find the common ratio
How do you find that
What does each number decrease by constantly if you multiply by what do you get the next term.
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divide one of the term by the previous one
i got 1/4
|dw:1389577102728:dw|
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