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Mathematics 18 Online
OpenStudy (anonymous):

3r^2-3r-270

OpenStudy (anonymous):

Question is?

OpenStudy (anonymous):

i have to factor it

OpenStudy (marigirl):

we can take out a common factor, what number do u think all the terms in your equation are a factor of? (i.e what number can each term be divided by)

OpenStudy (anonymous):

my teacher gave me the answer which is 3(r+9)(r-10) but we have to show our work to show that we know how to do it and honestly I always have trouble with these

OpenStudy (marigirl):

yes can u see that there is a 3 outside both brackets? that means in the equation 3r^2-3r-270, each term can be divided by 3... now if each term can be divided by 3, lets see what the next step of the equation will look like. ill start u off ... 3r^2-3r-270 3(r^2-r ..... what will be next

OpenStudy (anonymous):

90

OpenStudy (marigirl):

good. now the equation look like this 3r^2-3r-270 take 3 as the common factor out. 3(r^2-r-90)

OpenStudy (marigirl):

now we need to factorise inside the bracket... can u think of two numbers that will multiply to -90 and add to -1

OpenStudy (anonymous):

1?

OpenStudy (marigirl):

i need two numbers... that will multiply to -90 and add to -1

OpenStudy (anonymous):

1 and -1

OpenStudy (marigirl):

hmm both numbers need to multiply to -90

OpenStudy (marigirl):

but also add to -1

OpenStudy (anonymous):

9 and -10?

OpenStudy (marigirl):

YES :D

OpenStudy (marigirl):

all u need to do now is write them as such 3r^2-3r-270 take 3 as the common factor out. 3(r^2-r-90) now to factorise inside the bracket. think of two numbers that MULTIPLY to -90 but also ADD to -1 the numbers were -10 and +9 3(r-10(r+9)

OpenStudy (anonymous):

:D thanks

OpenStudy (marigirl):

no probs and thanx for the medal

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