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Mathematics 22 Online
OpenStudy (anonymous):

What would I do in this case? 100 sigma 2^3 i=0

OpenStudy (anonymous):

\[\sum_{i=0}^{100}2^{3}\] Is that the question?

OpenStudy (anonymous):

yes Icouldn't put the sigma in there

OpenStudy (anonymous):

Since there are no variable the summantion will look like this \[\sum_{i=0}^{n}c= nc -> \sum_{i=0}^{100}2^{3} = 100(2^{3})\]

OpenStudy (anonymous):

where c is a constant

OpenStudy (anonymous):

That would make the answer 800 then. Thank you!

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