Question

What is the general equation of a circle centered at the point (h, k)?

Answer 1

The equation of any general circle is (x-h)^2 + (y-k)^2 = r^2

The center is (h,k) and the radius is r.

Answer 2

thanks, would you mind telling me how to solve it if the center was (2,4) and the radius was 6? @jim_thompson5910

Answer 3

if the center was (2,4), then (h,k) = (2,4) meaning that h = 2 and k = 4

if the radius is 6, then r = 6

Answer 4

its really that simple?

Answer 5

(x-h)^2 + (y-k)^2 = r^2

(x-2)^2 + (y-4)^2 = r^2 ... plug in h = 2 and k = 4

(x-2)^2 + (y-4)^2 = 6^2 ... plug in r = 6

(x-2)^2 + (y-4)^2 = 36

Answer 6

yes it is once you get the hang of it

Answer 7

thanks for the help :) that makes these a lot easier

Answer 8

you're welcome