Mathematics
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OpenStudy (anonymous):
(y+1/3) (y-1/3)
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OpenStudy (anonymous):
You start by FOIL-ing this
OpenStudy (anonymous):
Do you know how to use FOIL?
OpenStudy (anonymous):
No I'm sorry, I don't can you explain
OpenStudy (anonymous):
FOIL is an acronym
OpenStudy (anonymous):
First Outer Inner Last
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OpenStudy (anonymous):
So you begin by multiplying the first ones
OpenStudy (anonymous):
y and y= y^2
OpenStudy (anonymous):
Does that part make sense?
OpenStudy (anonymous):
yes I see because first would be the 2 y's
OpenStudy (anonymous):
Yep so next is Inner
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OpenStudy (anonymous):
When you look at the two factors, you see how +1/3 and y are in the inside?
OpenStudy (anonymous):
Yes I see so Would that be y/3?
OpenStudy (anonymous):
Yes!
OpenStudy (anonymous):
Next is Outer, so y and -1/3 so -y/3
OpenStudy (anonymous):
Ok so do I have a new equation to do or is my answer y/3 - y/3?
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OpenStudy (raden):
alternatively, use the difference squre formula :
(a-b)(a+b) = a^2 - b^2
(y+1/3) (y-1/3) = y^2 - (1/3)^2 = ...
OpenStudy (anonymous):
Nope, sorry about that
OpenStudy (anonymous):
We are still missing the last one which is Last
OpenStudy (anonymous):
So 1/3 x (-1/3) = -1/9
OpenStudy (raden):
(1/3)^2 = 1/3 * 1/3 = 1/9
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OpenStudy (anonymous):
all together you get y^2-1/9
OpenStudy (anonymous):
Because it's y^2+1/3y-1/3y-1/9
OpenStudy (anonymous):
Thank you so much!! I think I understand this now!
OpenStudy (anonymous):
Awesome! No problem!