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Mathematics 23 Online
OpenStudy (anonymous):

(y+1/3) (y-1/3)

OpenStudy (anonymous):

You start by FOIL-ing this

OpenStudy (anonymous):

Do you know how to use FOIL?

OpenStudy (anonymous):

No I'm sorry, I don't can you explain

OpenStudy (anonymous):

FOIL is an acronym

OpenStudy (anonymous):

First Outer Inner Last

OpenStudy (anonymous):

So you begin by multiplying the first ones

OpenStudy (anonymous):

y and y= y^2

OpenStudy (anonymous):

Does that part make sense?

OpenStudy (anonymous):

yes I see because first would be the 2 y's

OpenStudy (anonymous):

Yep so next is Inner

OpenStudy (anonymous):

When you look at the two factors, you see how +1/3 and y are in the inside?

OpenStudy (anonymous):

Yes I see so Would that be y/3?

OpenStudy (anonymous):

Yes!

OpenStudy (anonymous):

Next is Outer, so y and -1/3 so -y/3

OpenStudy (anonymous):

Ok so do I have a new equation to do or is my answer y/3 - y/3?

OpenStudy (raden):

alternatively, use the difference squre formula : (a-b)(a+b) = a^2 - b^2 (y+1/3) (y-1/3) = y^2 - (1/3)^2 = ...

OpenStudy (anonymous):

Nope, sorry about that

OpenStudy (anonymous):

We are still missing the last one which is Last

OpenStudy (anonymous):

So 1/3 x (-1/3) = -1/9

OpenStudy (raden):

(1/3)^2 = 1/3 * 1/3 = 1/9

OpenStudy (anonymous):

all together you get y^2-1/9

OpenStudy (anonymous):

Because it's y^2+1/3y-1/3y-1/9

OpenStudy (anonymous):

Thank you so much!! I think I understand this now!

OpenStudy (anonymous):

Awesome! No problem!

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