help please!
On the interval 0 ≤ x ≤ 2 π , where are the asymptotes for the graph of y = cot(x - pi/2 ) located?

0, π and 2π
π and 2π
π/2 and 3π/2

Question

help please!
On the interval 0 ≤ x ≤ 2 π , where are the asymptotes for the graph of y = cot(x - pi/2 ) located?


0, π and 2π
π and 2π
π/2 and 3π/2 << i chose this!
π/2, π and 3π/2

mathmale · Answer

We could simplify this problem a little by asking, "Where is tan(x-pi/2) = 0 on [0,2pi]?  That's the easiest way to identify the asymptotes of the given function, because when tan(x-pi/2)=0, cot(x-pi/2) is undefinted.

anonymous · Answer

Answer is c. You are right

ttop0816 · Answer

@mathmale  then would my answer be correct or incorrect...??

anonymous · Answer

Correct

ttop0816 · Answer

@MayankD how about for this question if you dont mind! https://media.glynlyon.com/g_trg_2013/2/graph_sec(x-pi_2).gif y = csc(x - pi/2) <<< chose this! y = sec(x - pi/2)

anonymous · Answer

Its sec(x-pi/2)

anonymous · Answer

When in doubt substitute values and compare

ttop0816 · Answer

@MayankD  thank you so much! im correct for this too right..? im sorry if im bothering you!
The graph of y = tanx + 1 crosses the y-axis at _____.


-1
0
1<<
2

anonymous · Answer

Yes