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OpenStudy (anonymous):
OpenStudy (anonymous):
Or @anyone xD
OpenStudy (anonymous):
4x = 2x? as in x=0?
OpenStudy (anonymous):
I just says that lol, now that I think about it with other thoughts, I don't think its A?
OpenStudy (anonymous):
I wonder if it meant to say 4y = 2x?
as it sits, it reduces to 2=1
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OpenStudy (anonymous):
xD it would be much more simple that way ._.
ganeshie8 (ganeshie8):
the graphs must represent exponential functions : \(4^x = 2^x\)
OpenStudy (anonymous):
The top says "The graphs of four exponential functions are shown below" but you guys can clearly see that
OpenStudy (anonymous):
Yea, ofc :p
ganeshie8 (ganeshie8):
if so, then use this :- every exponential parent function cuts the y-axis at \(1\)
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ganeshie8 (ganeshie8):
so you may simply pick the curves that cut the y-axis at \(1\)
OpenStudy (anonymous):
So C and D .. are you sure lol ?
ganeshie8 (ganeshie8):
you need to be sure, not meh
ganeshie8 (ganeshie8):
\(4^x\)
put x = 0, wat do u get ?
OpenStudy (anonymous):
ô.ô I'm not ;~; thats why I'm asking
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ganeshie8 (ganeshie8):
to be sure, you need to knw why every exponential parent function cuts the y-axis at \(1\)
OpenStudy (anonymous):
could you explain at little bit further please
ganeshie8 (ganeshie8):
sure :)
OpenStudy (anonymous):
:>
OpenStudy (anonymous):
OHHH WAIT. 4^0 = 1 and 2^0 = 1
Is that why? Because the x represent 0?
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ganeshie8 (ganeshie8):
exponential parent function : \(y = a^x\)
A graph cuts y-axis, when its x-coordinate = 0.
so, lets plug \(x=0\) above and see wat we get for y-coordinate
\(y = a^0 = 1\)
thus, every exponential parent function cuts the y-axis at \(1\).
ganeshie8 (ganeshie8):
yess, i see you got it !
OpenStudy (anonymous):
Ermagod :D
OpenStudy (anonymous):
I'd give you a cookie :*
ganeshie8 (ganeshie8):
aww ty ty :))
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