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Chemistry 13 Online
OpenStudy (anonymous):

]How many atoms of cobalt would there be in a 2.2-gram sample of cobalt? 4.64 x 10^21 atoms 2.25 x 10^22 atoms 1.61 x 10^25 atoms 7.81 x 10^25 atoms

OpenStudy (anonymous):

Help PLEASE !!!! :(

OpenStudy (wolfe8):

Welcome to OpenStudy. Don't worry, I will try to help you. First, can you find the number of mole of cobalt you have?

OpenStudy (anonymous):

idk how to find the mole?

OpenStudy (wolfe8):

To navigate on that chart, note that to go from grams to moles, you have to divide by the molar mass.

OpenStudy (anonymous):

So it would be 1.61x10^25 ?

OpenStudy (anonymous):

help please :((((

OpenStudy (wolfe8):

Can you show me what you did? Do you know what the molar mass is for cobalt? This will help: http://www.ptable.com/

OpenStudy (anonymous):

molar mass is 59 ?

OpenStudy (anonymous):

to be exact its 58.93

OpenStudy (wolfe8):

Yes :) So you divide 2.2 by 58.93 to get the number of moles. Then you multiply it by the Avogadro's number given in the chart at the top.

OpenStudy (anonymous):

I don't see where the Avogadro's number is?

OpenStudy (wolfe8):

Ah it's not labeled that way in the chart. It is 6.02*10^23. It basically means the number of atoms/molecules in one mole of a substance

OpenStudy (anonymous):

oh okay, let me do the math then

OpenStudy (wolfe8):

Sure thing.

OpenStudy (anonymous):

so it would be 6.02x10^23 times 26.78?

OpenStudy (wolfe8):

26.78 is not the number of moles I get. Show me how you got that please

OpenStudy (anonymous):

I divided 58.93/2.2

OpenStudy (wolfe8):

It's the other way around hehe. Molar mass means how heavy 1 mol of the substance is.

OpenStudy (anonymous):

ohhhhh ok

OpenStudy (anonymous):

3.7x10^2 ?

OpenStudy (wolfe8):

Yup. And you multiply that with Avogadro's number.

OpenStudy (anonymous):

Ok thx

OpenStudy (anonymous):

do I add the exponents? or multiply them?

OpenStudy (wolfe8):

I believe you add them since you are multiplying the indices.

OpenStudy (anonymous):

Ok Perfect thanks!!

OpenStudy (wolfe8):

You're welcome. All the best. Do take time to read our CoC: http://openstudy.com/code-of-conduct And if you're satisfied with my response, you can give me a medal and close this question. :)

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