15.0 rams of Calcium is reacted with 10.0 grams of phosphorus to make calcium phosphide. what would be the limiing reagent?

Question

wolfe8 · Answer

Hello and welcome to OpenStudy. First, can you write out the balanced equation for this reaction?

anonymous · Answer

$$3Ca+2P \rightarrow Ca _{3}P _{2}$$ i think thats right

wolfe8 · Answer

Alright and it is balanced. Now, can you find out the number of moles of calcium and phosphorus?

anonymous · Answer

.374molCa and .323molP

wolfe8 · Answer

Divide those by the coefficients of the respective substances so that we have a 1:1 ratio and see which one is the lowest. That will be the limiting substance :)

anonymous · Answer

great thank you!

wolfe8 · Answer

You're welcome. I would explain more but I am kind of sleepy. Enjoy your stay. Do take time to read our CoC: http://openstudy.com/code-of-conduct Also, if you are satisfied with the question and my response, you can give me a medal and close it.